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|3%2√3|%三次根号64+(根号6)^3

√(1+2+........+n)-√(1+2+........+(n-1))=√[n(n+1)/2]-√[(n-1)n/2] (分子有理化得) =(√[n(n+1)/2]-√[(n-1)n/2])(√[n(n+1)/2]+√[(n-1)n/2])/(√[n(n+1)/2]+√[(n-1)n/2]) =n/(√[n(n+1)/2]+√[(n-1)n/2]) (分子分母同时除以n) =1/(√[(1+1/n)/2]+√[(1...

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